Number Systems
Since 12 is positive, one of the numbers must be positive because the sum of negative number is negative. If r is 13, then x = 0, y = -1, and z = 0, satisfy r + x + y + w= 2 and x < 6.
Related MCQ Number Systems
MOCK TEST SERIES
Since 12 is positive, one of the numbers must be positive because the sum of negative number is negative. If r is 13, then x = 0, y = -1, and z = 0, satisfy r + x + y + w= 2 and x < 6.